HELP PLEASE - Boat Tower Speaker Wiring

[rsharp2000]

I am wiring 4 MM651UM speakers on my boat tower and powering them via a Clarion 480XM 4-channel amplifier.
I have outlined the 4 options I see for configuring these components in the pic below and thought option #4 serial/parallel config would be best since:
1) Stereo imaging not really an issue for tower speakers.
2) only requires a 2 wire harness from tower to amp.
3) only requires 1 bridged channel (via bridging channels 3 & 4) & leaves channels 1 & 2 open for current bow speakers.
4) this config would also produce most available volume/power to speakers.
BUT when I power up this system the output volume of these 4 speakers is barely heard - NOT what I was expecting at all! I have 2 Polk MM650 speakers in the bow individually connected to channels 1 & 2 in standard stereo mode and these can be heard just fine. I obviously have got something wrong w/ the series/parallel config or my thinking for Option #4 outputs but can't figure out what !!??
I wired the 4 speakers in series then parallel and have the resultant single + wire connected to ch3+ on the amp and the - wire connected to ch4-. I have the amp channel 3/4 mode set in mono (if I switch to stereo I get nothing at all) and all filters off. Gain was left midway just like channels 1/2 for bow speakers. I could easily go to 8 wire harness & just hook up all 4 tower speakers in straight-forward stereo mode and move bow speakers to unused deck speaker outputs (Clarion CMD 04 head unit) - but really thought this parallel/serial config would be best trick way to maximize this setup.
Thanks in advance for ANY/ALL help GREATLY appreciated to resolve this for me!

[rsharp2000]

... here is a better drawing ...

[AuMDLST]

I believe your best option is senerio number one - reasoning:
#1 produces 80 watts per speaker
#2 actually produces 57.5 per because you have an 8 ohm load on the bridged 4 ohm channel
when bridged it is one new channel not the two you are thinking so the 8ohm load is going to cut the wattage in half
#3 is correct with a two ohm load on a 2ohm channel the 115 watts is shared for two speakers - 57.5 watts each
#4 results in a 4 ohm load on a 4 ohm bridged channel which is 4 speakers sharing 230 watts
each speaker only getting the 57.5 watts

[Mikeski]

#1 and #2 are the exact same from the amp and speaker perspective because there are internal jumpers between 1- to 2+ and 3- to 4+.

My vote is #2, you won't really see the same power from #4

[cdrymalla]

#1 and #2 are the exact same from the amp and speaker perspective because there are internal jumpers between 1- to 2+ and 3- to 4+.

My vote is #2, you won't really see the same power from #4

Is this true? I was under the impression that under option #2 (two 4ohm speakers in series bridged) you would end up with an 8ohm load, thereby cutting the power in half.

I am new to this stuff and I was looking at how to do the same thing with a Kenwood KAC-8405. In my case, I was looking to bridge a pair of polk momos (4 total speakers) into each of channels 1-2 and channels 3-4. The amp is rated at 180W RMSx2 bridged 4 Ohms).

So if this is the case, as Mikeski, stated, it would be the same output as #1 (each speaker hooked up to a single channel), but with less wires - which is what I am trying to do since I already have two sets wires already routed - one set of wires going to each can.